Import Question JSON

Current Question (ID: 10969)

Question:
$\text{0.284 g of an organic substance gave 0.287 g AgCl in a carius method for the estimation of halogen. The percentage of Cl in the compound is-}$
Options:
  • 1. $5\%$
  • 2. $18\%$
  • 3. $25\%$ (Correct)
  • 4. $33\%$
Solution:
$\text{Hint: } \% \text{ of chlorine} = \frac{35.5}{143.5} \times \frac{\text{amount of AgCl}}{\text{amount of organic compound}} \times 100\%$ $\text{Step 1:}$ $\text{Weight of the organic substance = 0.284 g}$ $\text{Weight of AgCl is = 0.287 g}$ $\text{143.5 g of AgCl contains 35.5 g of chlorine}$ $\text{0.287 g of AgCl contains } \frac{35.5}{143.5} \times 0.287$ $\text{Step 2:}$ $\% \text{ of chlorine} = \frac{35.5}{143.5} \times \frac{\text{amount of AgCl}}{\text{amount of organic compound}} \times 100\%$ $\% \text{ of chlorine is } \frac{35.5}{143.5} \times \frac{0.287}{0.284} \times 100 = 24.98\%$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}