Import Question JSON

Current Question (ID: 10970)

Question:

$\text{0.26 g of an organic compound gave 0.039 g of water and 0.245 g of carbon dioxide on combustion. The percentage of C in the organic compound is-}$

Options:

1. $35\%$
2. $25\%$ (Correct)
3. $2\%$
4. $90\%$

Solution:

$\text{Hint: Mole concept}$ $\text{Step 1:}$ $\text{Weight of organic compound = 0.26g}$ $\text{Weight of water = 0.039g}$ $\text{Weight of CO}_2 = \text{0.245g}$ $\text{Step 2:}$ $\text{Percentage of carbon}$ $\text{44 g of CO}_2\text{ contain 12 g of C}$ $\text{0.245 g of CO}_2\text{ contains } \frac{12}{44} \times 0.245\text{ g of C}$ $\text{% of Carbon} = \frac{12}{44} \times \frac{0.245}{0.26} \times 100 = 25.69\%$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}