Import Question JSON

Current Question (ID: 10972)

Question:

$\text{0.3780 grams of an organic chloro compound gave 0.5740 grams of silver chloride in Carius estimation. % of chlorine present in the compound is -}$

Options:

1. $25\%$
2. $37.59\%$ (Correct)
3. $42\%$
4. $05.70\%$

Solution:

$\text{Hint: 1 mol of AgCl contains 1 mol of Cl.}$ $\text{Step 1:}$ $\text{Given that,}$ $\text{Mass of the organic compound is 0.3780 g.}$ $\text{Mass of AgCl formed = 0.5740 g}$ $\text{Thus, the mass of chlorine in 0.5740 g of AgCl}$ $= \frac{35.5 \times 0.5740}{143.32}$ $= 0.1421 \text{ g}$ $\text{Step 2:}$ $\text{Percentage of chlorine} = \frac{0.1421}{0.3780} \times 100 = 37.59\%$ $\text{Hence, the percentage of chlorine present in the given organic chloro compound is}$ $37.59\%.$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}