Import Question JSON

Current Question (ID: 10981)

Question:

$\text{0.24 g of an organic compound containing phosphorous gave 0.66 g of }\text{Mg}_2\text{P}_2\text{O}_7\text{ by the usual analysis. The percentage of phosphorous in the compound is-}$

Options:

1. $77\%$ (Correct)
2. $72\%$
3. $87\%$
4. $60\%$

Solution:

$\text{Hint: Percentage of phosphorus} = \frac{62 \times m_1}{222 \times m} \times 100$ $\text{Step 1: Given data and molecular mass relationship}$ $\text{Weight of an organic compound} = 0.24 \text{ g}$ $\text{Weight of }\text{Mg}_2\text{P}_2\text{O}_7 = 0.66 \text{ g}$ $\text{222 g of }\text{Mg}_2\text{P}_2\text{O}_7\text{ contains 62 g of P}$ $\text{0.66 g }\text{Mg}_2\text{P}_2\text{O}_7\text{ contains} = \frac{62}{222} \times \frac{0.66}{0.24} \text{ g of P}$ $\text{Step 2: Calculate percentage of phosphorus}$ $\text{Percentage of P} = \frac{62}{222} \times \frac{0.66}{0.24} \times 100 = 76.80\%$ $\text{Rounding to nearest whole number gives 77%}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}