Import Question JSON

Current Question (ID: 11003)

Question:

$\text{When a bicycle tyre suddenly bursts, the air inside the tyre expands. This process is:}$

Options:

1. $\text{isothermal}$
2. $\text{adiabatic}$ (Correct)
3. $\text{isobaric}$
4. $\text{isochoric}$

Solution:

$\text{The sudden bursting of a bicycle tyre is a very rapid process. When the air expands rapidly, there is no time for heat to be exchanged with the surroundings. A thermodynamic process where no heat is exchanged between the system and its surroundings is called an adiabatic process.}\n\n\text{Here's a breakdown of the other options:}\n\n\text{1. Isothermal: A process where the temperature remains constant. This is not the case in a sudden expansion, as the gas cools.}\n\n\text{3. Isobaric: A process where the pressure remains constant. The pressure of the gas changes significantly during the expansion.}\n\n\text{4. Isochoric: A process where the volume remains constant. In this case, the volume of the gas is increasing as it escapes into the atmosphere.}\n\n\text{Therefore, the sudden expansion of air from a bursting tyre is an example of an adiabatic process. This is because the process is so rapid that there is no time for the system (the expanding gas) to transfer heat to or from the surroundings.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}