Import Question JSON

Current Question (ID: 11048)

Question:

$\text{The latent heat of vaporisation of water is 2240 J/gm. If the work done in the process of expansion of 1 g is 168 J, then the increase in internal energy is:}$

Options:

1. $2408 \text{ J}$
2. $2240 \text{ J}$
3. $2072 \text{ J}$ (Correct)
4. $1904 \text{ J}$

Solution:

$\text{Hint: } \Delta Q = \Delta U + \Delta W$ $\text{Step: Find the increase in internal energy of the water.}$ $\text{From the first law of thermodynamics we get;}$ $\Delta Q = \Delta U + \Delta W$ $\Rightarrow \Delta U = \Delta Q - \Delta W$ $\Rightarrow \Delta U = 1 \times 2240 - 168 = 2072 \text{ J} \quad [\Delta Q = mL]$ $\Rightarrow \Delta U = 2072 \text{ J}$ $\text{Hence, option (3) is the correct answer.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}