Import Question JSON

Current Question (ID: 11138)

Question:
$\text{Without change in temperature, a gas is forced in a smaller volume. Its pressure increases because its molecules:}$
Options:
  • 1. $\text{strike the unit area of the container wall more often.}$ (Correct)
  • 2. $\text{strike the unit area of the container wall at a higher speed.}$
  • 3. $\text{strike the unit area of the container wall with greater force.}$
  • 4. $\text{have more energy.}$
Solution:
$\text{According to the Kinetic Molecular Theory of gases, pressure is a result of the collision of gas molecules with the walls of the container. If the temperature is constant, the average kinetic energy and the speed of the gas molecules remain the same. When the volume of the container is decreased, the number of molecules per unit volume increases. This leads to a higher frequency of collisions of the molecules with the container walls. As a result, the pressure increases. So, the correct option is 1.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}