Import Question JSON

Current Question (ID: 11320)

Question:

The evolution of C₄ photosynthetic system is probably one of the strategies for

Options:

1. Maximising the availability of CO₂ and minimising the loss of H₂O
2. Minimising the loss of O₂ and maximising the availability of H₂O
3. Minimising the availability of CO₂ and maximising the loss of H₂O
4. More than one option is correct

Solution:

C₄ photosynthesis is an adaptation in some plants that allows for increased efficiency in carbon fixation under high light intensities and high temperatures. C₄ plants have evolved a specialized leaf anatomy, called Kranz anatomy, where mesophyll cells are surrounded by bundle sheath cells. The initial fixation of CO₂ occurs in mesophyll cells, where it is incorporated into a four-carbon molecule. This molecule is then transported into bundle sheath cells where it is broken down to release CO₂, which then enters the Calvin cycle. This process allows C₄ plants to efficiently concentrate CO₂ around the enzyme Rubisco, which is involved in the Calvin cycle, and minimize the loss of water by reducing the need for stomatal opening. This results in higher water-use efficiency compared to C₃ plants, which directly fix CO₂ in mesophyll cells.

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}