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Current Question (ID: 11349)

Question:

During light reaction in photosynthesis, the following are formed

Options:

1. ATP and sugar
2. hydrogen, O₂ and sugar
3. ATP, hydrogen donor and O₂
4. ATP, hydrogen and O₂ donor

Solution:

During the light-dependent reactions of photosynthesis, the following are formed: ATP: This is formed by the phosphorylation of ADP using energy from the light energy absorbed by the photosystems. Hydrogen donor: This is NADPH+H⁺. It is formed by the reduction of NADP⁺ using electrons from the electron transport chain. O₂: This is produced as a byproduct of water splitting during the photosystem II reaction. Water molecules are split into hydrogen ions (H⁺), electrons, and molecular oxygen (O₂). Therefore, the correct option is option 3 - ATP, hydrogen donor (NADPH+H⁺), and O₂ are formed during the light reactions of photosynthesis. Sugar is not directly formed during the light reactions, but the ATP and NADPH+H⁺ produced in the light reactions are used in the subsequent dark reactions to fix CO₂ and synthesize sugars through the Calvin cycle.

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}