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Current Question (ID: 11364)

Question:

Which of the following is incorrect about the light reactions of photosynthesis?

Options:

1. P₆₈₀ and P₇₀₀ are the reaction centres of PS-I and PS-II respectively
2. Light energy provides energy for the photolysis of water through excitation of the reaction centre of PS-II
3. NADPH is not produced in cyclic electrons transport in light reactions
4. Reactions of the two photosystems are needed for the reduction of NADP

Solution:

(1) In photosystem (PS-I), the photocentre is a special chlorophyll-a molecule called P₇₀₀. It is active in both red and far-red light, while a very small amount of special form of chlorophyll-a called P₆₈₀ constitutes the reaction centre of photosystems-II (PS-II), which is inactive in far-red light (beyond 680 nm).

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Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}