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Current Question (ID: 11378)

Question:

How many of the following statements are correct? i. Products of dark reaction are substrates of light reaction. ii. Products of light reaction are substrates of dark reaction. iii. In the stroma, enzymatic reactions incorporate CO₂ into the plant leading to the synthesis of sugar. iv. Dark reactions are directly light-driven. v. Chloroplast is a single membranous organelle.

Options:

1. 2
2. 3
3. 4
4. 1 (Correct)

Solution:

CO₂, NADPH + H⁺, and ATP are the substrates for dark reactions. The products of the light reactions are ATP, NADPH, and oxygen. That means products of the light reaction are substrates of dark reaction. So, statement (ii) is correct and statement (i) is wrong. The fixation of carbon dioxide and the formation of carbohydrates takes place in the chloroplast present in plant cells. In the stroma, enzymatic reactions incorporate CO₂ into the plant leading to the synthesis of sugar, which in turn forms the starch. So, statement (iii) is correct. Dark reactions are not directly light-driven but are dependent on the products of light reactions. So, statement (iv) is incorrect. Chloroplasts are bounded by a double membrane called the chloroplast envelope. So, statement (v) is incorrect.

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Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}