Import Question JSON

Current Question (ID: 11380)

Question:

Read the following four statements A, B, C and D and select the right option having both correct statements: STATEMENTS: (A) Z-scheme of light reaction takes place in the presence of PSI only (B) Only PSI functional in cyclic photophosphorylation (C) Cyclic photophosphorylation results in a synthesis of ATP and NADPH₂ (D) Stroma lamellae lack PSII as well as NADP

Options:

1. A and B
2. B and C
3. C and D
4. B and D

Solution:

Statement B is correct: In cyclic photophosphorylation, only PSI (Photosystem I) is functional, while PSII (Photosystem II) is not involved. During this process, electrons are recycled back to PSI, and ATP is synthesized. Statement D is correct: Stroma lamellae lack PSII as well as NADP, which means that they do not contain Photosystem II or the NADP reductase enzyme, which are involved in the non-cyclic photophosphorylation pathway. Statement A is incorrect: The Z-scheme of light reaction takes place in the presence of both Photosystem I and Photosystem II, and not just PSI. Statement C is also incorrect: The cyclic photophosphorylation pathway results in the synthesis of only ATP and not NADPH₂, as no water splitting occurs, and therefore no oxygen or NADPH₂ is produced.

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}