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Current Question (ID: 11409)

Question:

The first step for initiation of photosynthesis will be:

Options:

1. Photolysis of water
2. Excitement of chlorophyll molecule due to absorption of light
3. ATP formation
4. Glucose formation

Solution:

Photosynthesis is the process by which green plants and other photosynthetic organisms convert light energy into chemical energy in the form of glucose or other organic molecules. The process involves two sets of reactions: the light-dependent reactions and the light-independent reactions. In the light-dependent reactions, light energy is absorbed by the pigment chlorophyll, which is located in the thylakoid membranes of the chloroplasts. This energy excites the electrons in the chlorophyll molecule and sets off a chain of reactions that result in the formation of ATP and NADPH, which are used to power the light-independent reactions. The photolysis of water (option 1) occurs during the light-dependent reactions and provides electrons and protons that are used to generate ATP and NADPH. ATP formation (option 3) is a result of the light-dependent reactions and not the first step of photosynthesis. Glucose formation (option 4) occurs during the light-independent reactions and requires the products of the light-dependent reactions.

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}