Import Question JSON

Current Question (ID: 11414)

Question:

Cyclic photophosphorylation is different from non-cyclic photophosphorylation as the former

Options:

1. Is performed by a collaboration of both PS-II and PS-I
2. Does not require any external source of electrons
3. Is connected with photolysis of water
4. Is connected with ATP and NADPH production

Solution:

Cyclic photophosphorylation is a process in which only photosystem I (PS-I) is involved, and it does not involve the photosystem II (PS-II) or photolysis of water. In cyclic photophosphorylation, the electrons excited by light energy from PS-I are transported through a series of electron carriers in the thylakoid membrane and then returned to PS-I. As a result, ATP is generated but not NADPH or O₂. Unlike non-cyclic photophosphorylation, cyclic photophosphorylation does not require any external source of electrons.

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}