Import Question JSON

Current Question (ID: 11448)

Question:
For the synthesis of one glucose molecule, the Calvin cycle operates for:
Options:
  • 1. 2 times
  • 2. 4 times
  • 3. 6 times
  • 4. 8 times
Solution:
For the synthesis of one glucose molecule, the Calvin cycle operates for 6 times. The Calvin cycle, also known as the light-independent reactions, occurs in the stroma of the chloroplasts and uses the energy-rich molecules ATP and NADPH₂, produced during the light-dependent reactions, to fix CO₂ and synthesize glucose. During the Calvin cycle, each turn of the cycle fixes one molecule of CO₂ and produces one molecule of glyceraldehyde-3-phosphate (G3P). Two G3P molecules can combine to form glucose. Therefore, it takes six turns of the Calvin cycle to synthesize two G3P molecules, which then combine to form one glucose molecule.

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Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}