Import Question JSON

Current Question (ID: 11456)

Question:

With reference to factors affecting the rate of photosynthesis, which of the following statements is not correct?

Options:

1. Light saturation for CO₂-fixation occurs at 10% of full sunlight.
2. Increasing atmospheric CO₂ concentration upto 0.05% can enhance the CO₂-fixation rate
3. C₃ plants respond to higher temperature with enhanced photosynthesis, while C₄ plants have a much lower temperature optimum.
4. Tomato is a greenhouse crop, which can be grown in a CO₂-enriched atmosphere for higher yield.

Solution:

(3) In C₄-plants, the initial fixation of CO₂ occurs in mesophyll cells. The primary acceptor of CO₂ is Phosphoenol Pyruvate (PEP). It combines with CO₂ in the presence of enzyme PEP carboxylase to form the first stable product, i.e., oxaloacetic Acid (OAA). C₃ plants lack PEPcarboxylase enzyme. They posses RuBisCO enzyme. This enzyme can work as both carboxylase (fixation of CO₂) and oxygenase (fixation of O₂). RuBisCO has much greater affinity for CO₂ than for O₂ and the binding is competitive. At higher temperature, its affinity for CO₂ decrease and it works as oxygenase. Therefore, at higher temperature photosynthesis decrease in C₃-plants, while in C₄-plants increases.

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}