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Current Question (ID: 11463)

Question:

Column - I i. Jan Ingenhousz ii. Joseph Priestley iii. T.W Engelmann iv. Julius von Sachs Column - II a. discovery of O₂ b. Plants restore to the air whatever breathing animals and burning candles remove c. showed that only the green part of the plants could release oxygen d. discovery of production of glucose in plants e. first action spectrum of photosynthesis Using a prism he split light into its spectral components and then illuminated Cladophora, placed in a suspension of aerobic bacteria. Which of the following shows the correct match?

Options:

1. i-c; ii-b; iii-a, e, f; iv-d
2. i-a, b; ii-c; iii-d; iv- e, f.
3. i-a; ii- b; iii- c, e; iv-f.
4. i-c, ii-a,b; iii-e, f; iv-d;

Solution:

EXPLANATION NCERT Reference: PAGE 208, XI NCERT

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}