Import Question JSON

Current Question (ID: 11466)

Question:

Respiration is

Options:

1. Breaking of a type of bonds like ionic or non ionic of complex compounds through oxidation within the cell by utilizing bulk of energy
2. Breaking of C-C bonds of simple molecules through hydrolysis within the cell by releasing energy
3. Breaking of C-C bonds of complex molecules through oxidation within the cell to release considerable amount of energy
4. Breaking of C-C bonds of complex molecules through hydrolysis within the cell by releasing energy

Solution:

Respiration is the process of breaking down complex organic molecules (such as glucose) through a series of oxidation reactions that release energy. The energy released is then stored in the form of ATP (adenosine triphosphate), which is the energy currency of the cell. This process occurs in the presence of oxygen (aerobic respiration) or without oxygen (anaerobic respiration). In aerobic respiration, the final electron acceptor is oxygen, which is reduced to water, whereas in anaerobic respiration, other molecules such as sulfate or nitrate are used as the final electron acceptor.

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}