Import Question JSON

Current Question (ID: 11478)

Question:

Conversion of glucose to glucose-6-phosphate, the first irreversible reaction of glycolysis, is catalyzed by:

Options:

1. Phosphofructokinase
2. Aldolase
3. Hexokinase
4. Enolase

Solution:

Hexokinase catalyzes the conversion of glucose to glucose-6-phosphate in the first step of glycolysis. This reaction requires the input of one molecule of ATP to phosphorylate the glucose molecule and make it more reactive. Phosphofructokinase is an enzyme involved in the third step of glycolysis, which catalyzes the conversion of fructose-6-phosphate to fructose-1,6-bisphosphate. Aldolase is an enzyme involved in the cleavage of fructose-1,6-bisphosphate into dihydroxyacetone phosphate and glyceraldehyde-3-phosphate in the fourth step of glycolysis. Enolase is an enzyme involved in the ninth step of glycolysis, which catalyzes the conversion of 2-phosphoglycerate to phosphoenolpyruvate.

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}