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Current Question (ID: 11492)

Question:

Fermentation- Which of the following is true?

Options:

1. Only partial breakdown of glucose
2. Net gain of only two molecules of ATP for each molecule of Glucose
3. NADH is oxidized to NAD⁺ rather slowly in fermentation
4. All of these

Solution:

(1) Fermentation is the partial breakdown of glucose in the absence of oxygen, which results in the production of various end products like lactic acid, ethanol, and carbon dioxide. (2) The net gain of ATP in fermentation is only two molecules of ATP for each molecule of glucose, which is much lower compared to aerobic respiration. (3) NADH is oxidized to NAD⁺ during fermentation, which is important to regenerate NAD⁺ for glycolysis to continue. This process occurs slowly in fermentation, leading to a buildup of NADH which can inhibit glycolysis.

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Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}