Import Question JSON

Current Question (ID: 11509)

Question:

The primary role of oxygen in cellular respiration is to:

Options:

1. yield energy in the form of ATP as it is passed down the respiratory chain.
2. act as an acceptor for electrons and hydrogen, forming water
3. combine with carbon, forming CO₂.
4. combine with lactate, forming pyruvate.

Solution:

The primary role of oxygen in cellular respiration is to act as an acceptor for electrons and hydrogen, forming water. This occurs during the electron transport chain, which is the final stage of cellular respiration. The electron transport chain uses the electrons and hydrogen ions produced during the earlier stages of cellular respiration (glycolysis, the Krebs cycle) to create a proton gradient across the inner mitochondrial membrane. Oxygen accepts the electrons and hydrogen ions at the end of the electron transport chain, combining with them to form water. This process generates a large amount of ATP, which is used to power cellular processes. Therefore, option 2, i.e., act as an acceptor for electrons and hydrogen, forming water, is the correct answer. Option 1 is partially correct, as oxygen does help yield energy in the form of ATP as it is passed down the respiratory chain, but its primary role is electron and hydrogen acceptor. Option 3 is incorrect because oxygen does not combine with carbon to form CO₂ during cellular respiration, but rather CO₂ is produced during earlier stages of cellular respiration such as the Krebs cycle. Option 4 is also incorrect because oxygen does not combine with lactate to form pyruvate, but rather lactate is converted to pyruvate during earlier stages of cellular respiration.

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}