Import Question JSON

Current Question (ID: 11513)

Question:

During Aerobic respiration, one molecule of Glucose gives

Options:

1. A net gain of 38 ATPs
2. Production of 38 ATPs
3. Production of 32 ATPs
4. Production of 36 ATPs

Solution:

During aerobic respiration, one molecule of glucose gives a net gain of 36 ATPs. This is because glucose undergoes glycolysis, the Krebs cycle, and oxidative phosphorylation to produce ATP. In glycolysis, two molecules of ATP are produced, and in the Krebs cycle, two more molecules of ATP are produced. The bulk of the ATP, however, is produced in oxidative phosphorylation, where electrons from NADH and FADH₂ are passed through the electron transport chain and ATP is generated by oxidative phosphorylation. The process of oxidative phosphorylation produces around 32-34 molecules of ATP, depending on the source of the electrons entering the electron transport chain. Therefore, the net gain of ATP from one molecule of glucose is around 36-38 molecules of ATP.

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}