Import Question JSON

Current Question (ID: 11518)

Question:

Pyruvate is a result of ...... of carbohydrates.

Options:

1. Glycolytic fermentation
2. Glycolytic aerobic respiration
3. Glycolytic catabolism
4. Glycolytic anabolism

Solution:

Pyruvate is a result of glycolytic catabolism of carbohydrates. During glycolysis, glucose is broken down into two molecules of pyruvate with the help of several enzymes and coenzymes. The process of glycolysis occurs in the cytoplasm of the cell and is anaerobic, meaning it does not require oxygen. Pyruvate can then be further oxidized in aerobic conditions through the process of oxidative decarboxylation to form acetyl CoA, which enters the Krebs cycle in the mitochondria.

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}