Import Question JSON

Current Question (ID: 11538)

Question:

Which statement is wrong for Krebs' cycle? 1. There are three points in the cycle where NAD⁺ is reduced to NADH + H⁺ 2. There is one point in the cycle where FAD⁺ is reduced to FADH₂ 3. During conversion of succinyl Co-A to succinic acid, a molecule of GTP is synthesised 4. The cycle starts with condensation of acetyl group (acetyl Co-A) with pyruvic acid to yield citric acid

Options:

1. There are three points in the cycle where NAD⁺ is reduced to NADH + H⁺
2. There is one point in the cycle where FAD⁺ is reduced to FADH₂
3. During conversion of succinyl Co-A to succinic acid, a molecule of GTP is synthesised
4. The cycle starts with condensation of acetyl group (acetyl Co-A) with pyruvic acid to yield citric acid

Solution:

Option 4 is incorrect, which can be corrected as: Krebs' cycle starts with the condensation of acetyl group with oxaloacetic acid and water to yield citric acid. During conversion of succinic acid to fumaric acid FAD is reduced to FADH₂. During conversion of pyruvic acid to acetyl Co-A, isocitrate to oxalosuccinic acid and α-ketoglutaric acid to succinyl Co-A NAD⁺ is reduced to NADH+H⁺

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}