Import Question JSON

Current Question (ID: 11576)

Question:

During which stage in the complete oxidation of glucose are the greatest number of ATP molecules formed from ADP:

Options:

1. Glycolysis
2. Krebs cycle
3. Electron transport chain
4. Conversion of pyruvic acid to acetyl CoA

Solution:

The greatest number of ATP molecules are formed during the electron transport chain (ETC), which is the final stage in the complete oxidation of glucose. During the ETC, NADH and FADH₂ produced in earlier stages of cellular respiration donate electrons to the electron transport chain, which then uses the energy released from this electron transfer to pump protons (H⁺) across the inner mitochondrial membrane from the matrix to the intermembrane space. This generates a proton gradient, and the potential energy of this gradient is then used to drive the synthesis of ATP by ATP synthase. The process by which ATP is synthesized by ATP synthase using the energy of the proton gradient is called oxidative phosphorylation. Overall, oxidative phosphorylation produces a total of 26-28 ATP molecules from one molecule of glucose, depending on the specific shuttle mechanism used to transport electrons from the cytosol into the mitochondria.

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}