Import Question JSON

Current Question (ID: 11791)

Question:

Which of the following taxonomic categories contains organisms least similar to one another?

Options:

1. Class
2. Genus
3. Family
4. Species

Solution:

In the taxonomic hierarchy, class is a higher taxonomic category that includes multiple orders, families, genera, and species. Organisms classified in the same class share relatively fewer similarities compared to organisms classified in lower taxonomic categories such as genus, family, or species. Genus, family, and species are more specific taxonomic categories and contain organisms that are more similar to one another. Organisms within the same genus are closely related and share many similarities. Organisms within the same family are more distantly related than those within the same genus, but still share some common characteristics. Organisms within the same species are the most similar, as they can interbreed and produce viable offspring. On the other hand, organisms within the same class may have diverse characteristics and evolutionary histories. Class is a broader taxonomic category that encompasses multiple orders, families, genera, and species, and may include organisms that have relatively less similarity compared to lower taxonomic categories.

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}