Import Question JSON

Current Question (ID: 11860)

Question:

Which out of the following was not the basis of the five kingdom classification?

Options:

1. Cell structure
2. Thallus organization
3. Phylogenetic Relationship
4. Gross morphology

Solution:

Gross morphology, or the overall physical appearance or form of an organism, was not one of the primary bases of the five kingdom classification system proposed by Robert Whittaker. The five kingdom classification system was based on several other factors, including cell structure (prokaryotic vs. eukaryotic), thallus organization (unicellular vs. multicellular), and phylogenetic relationship (evolutionary relatedness based on genetic and biochemical characteristics). The five kingdoms proposed by Whittaker were Monera (prokaryotic organisms), Protista (eukaryotic organisms with diverse characteristics), Fungi (eukaryotic fungi), Plantae (eukaryotic plants), and Animalia (eukaryotic animals). Gross morphology was not a primary criterion for classification in this system.

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}