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Current Question (ID: 11863)

Question:

Which of the following statement is wrong with respect to two Kingdom classification?

Options:

1. Developed at the time of Linnaeus
2. Used till very recently
3. Could distinguish between photosynthetic and non-photosynthetic
4. Easy to do and easy to understand

Solution:

The statement "Could distinguish between photosynthetic and non-photosynthetic" is incorrect with respect to two Kingdom classification. The two-kingdom classification system, developed by Carolus Linnaeus in the 18th century, categorized living organisms into two kingdoms: Plantae (for plants) and Animalia (for animals). This system was used until very recently, but it did not distinguish between photosynthetic and non-photosynthetic organisms. In the two-kingdom classification system, all photosynthetic organisms, including algae and bacteria, were classified under the kingdom Plantae, which led to an incorrect grouping of diverse organisms with different characteristics. For example, fungi, which are non-photosynthetic organisms, were also classified under Plantae, despite being distinct from plants in terms of their cellular structure and mode of nutrition.

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}