Import Question JSON

Current Question (ID: 11874)

Question:

$\text{Identify the blanks in the following figures -}$ $\text{The figure shows two diagrams: one of a dividing bacteria and another of Nostoc. Both diagrams have labeled parts A, B, C, D, and E that need to be identified.}$

Options:

1. $\text{A - Cell wall, B - Cell membrane, C - Heterocyst, D - DNA, E - mucilaginous sheath.}$
2. $\text{A - Cell wall, B - Cell membrane, C - DNA, D - Heterocyst, E - Mucilaginous sheath.}$ (Correct)
3. $\text{A - Mucilaginous sheath, B - Cell membrane, C - DNA, D - Heterocyst, E - Cell wall.}$
4. $\text{A - Cell membrane, D - Cell wall, C - DNA, D - Heterocyst, E - Mucilaginous sheath.}$

Solution:

$\text{Looking at the diagrams:}$ $\text{For the dividing bacteria (left diagram):}$ $\text{- A points to the outermost layer, which is the cell wall}$ $\text{- B points to the inner layer beneath the cell wall, which is the cell membrane}$ $\text{- C points to the genetic material in the center, which is DNA}$ $\text{For the Nostoc (right diagram):}$ $\text{- D points to the specialized thick-walled cell, which is a heterocyst}$ $\text{- E points to the outer gelatinous covering, which is the mucilaginous sheath}$ $\text{Heterocysts are specialized cells in cyanobacteria like Nostoc that are involved in nitrogen fixation. They have thick walls to protect the nitrogen-fixing enzymes from oxygen.}$ $\text{The mucilaginous sheath is a protective gelatinous layer that surrounds the entire filament of Nostoc.}$ $\text{Therefore, the correct identification is:}$ $\text{A - Cell wall, B - Cell membrane, C - DNA, D - Heterocyst, E - Mucilaginous sheath.}$ $\text{The correct answer is option (2).}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}