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Current Question (ID: 11909)

Question:
In case of protists sexual reproduction can be by
Options:
  • 1. Cell fusion
  • 2. Zygote formation
  • 3. Triple fusion
  • 4. Both 1 and 2
Solution:
Protists, which are a diverse group of eukaryotic microorganisms, exhibit various modes of sexual reproduction. Cell fusion (option 1) and zygote formation (option 2) are two common methods of sexual reproduction in protists. In cell fusion, two haploid cells fuse to form a diploid zygote, which then undergoes meiosis to produce haploid offspring. In zygote formation, two haploid cells, often referred to as gametes, fuse to form a diploid zygote, which then develops into a mature organism. Triple fusion (option 3) is a process that occurs during fertilization in angiosperms, which are flowering plants, and is not a method of sexual reproduction in protists.

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}