Import Question JSON

Current Question (ID: 11926)

Question:

Saprophytic protists are:

Options:

1. Slime moulds
2. Dinoflagellates
3. Chrysophytes
4. Protozoans

Solution:

Page 21, XI NCERT. Saprophytic protists are organisms that obtain nutrients by decomposing dead organic matter. Slime moulds, which are part of the kingdom Protista, are examples of saprophytic protists. Slime moulds typically feed on dead plant material or other organic matter, and they play an important role in recycling nutrients in ecosystems. Dinoflagellates (option 2) and chrysophytes (option 3) are not typically saprophytic protists. Dinoflagellates are a diverse group of marine and freshwater protists that can be autotrophic or heterotrophic, and they are known for their unique shape and characteristics. Chrysophytes are a group of protists that include diatoms, golden algae, and brown algae, and they are primarily photosynthetic, although some species may also exhibit mixotrophic or parasitic behaviours. Protozoans (option 4) are a group of protists that are primarily heterotrophic and include various types of microscopic animals, such as amoebas, flagellates, ciliates, and sporozoans. They typically obtain nutrients through predation, engulfing other smaller organisms, or through absorption, but they are not typically saprophytic.

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}