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Current Question (ID: 11948)

Question:
How many of the following statements regarding fungi are true? I. Asexual reproduction is common by the formation of spores. II. Their bodies consist of hyphae that may be interconnected to form mycelium. III. They secrete digestive enzymes onto organic matter and then absorb the products of the digestion. IV. Fungi can break down almost any carbon containing product. V. Fungi do not enter symbiotic relationships.
Options:
  • 1. 2 (Correct)
  • 2. 3
  • 3. 4
  • 4. 5
Solution:
Statements II, III and IV are true regarding fungi. Statement II is true, as the bodies of fungi consist of hyphae that may be interconnected to form mycelium. Fungi secrete digestive enzymes onto organic matter and then absorb the products of digestion. This process, known as extracellular digestion, allows fungi to break down complex organic materials into simpler compounds that can be absorbed and utilized for their nutrition. Fungi are known for their ability to break down a wide range of carbon-containing products, including plant material, wood, dead animals, and even some synthetic materials. Statements I and V are not true. Statement I is not entirely accurate, as asexual reproduction in fungi can occur through various methods, not just by the formation of spores. Statement V is not true, as fungi can indeed enter symbiotic relationships with other organisms, such as mycorrhizal associations with plants.

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}