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Current Question (ID: 12061)

Question:
A charged particle having drift velocity of 7.5 × 10⁻⁴ ms⁻¹ in an electric field of 3 × 10⁻¹⁰ Vm⁻¹, has mobility of:
Options:
  • 1. 2.5 × 10⁶ m²V⁻¹s⁻¹
  • 2. 2.5 × 10⁻⁶ m²V⁻¹s⁻¹
  • 3. 2.25 × 10⁻¹⁵ m²V⁻¹s⁻¹
  • 4. 2.25 × 10¹⁵ m²V⁻¹s⁻¹
Solution:
Hint: μ = vₑ/E Step: Find the mobility of a charged particle. The drift velocity of the electrons depends on the strength of the electric field. The formula of mobility is given by; μ = vₑ/E μ = 7.5×10⁻⁴ / 3×10⁻¹⁰ ⇒ μ = 2.5 × 10⁶ m²V⁻¹s⁻¹ Hence, option (1) is the correct answer.

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}