Import Question JSON

Current Question (ID: 12088)

Question:

Which one of the following statements is wrong? 1. Algin and carrageenan are products of algae 2. Agar-agar is obtained from Gelidium and Gracilaria 3. Chlorella and Spirulina are used as space food 4. Mannitol is stored food in Rhodophyceae

Options:

1. Algin and carrageenan are products of algae
2. Agar-agar is obtained from Gelidium and Gracilaria
3. Chlorella and Spirulina are used as space food
4. Mannitol is stored food in Rhodophyceae

Solution:

Mannitol is not a stored food in Rhodophyceae (red algae). Mannitol is a sugar alcohol that serves as a carbohydrate storage compound in some other types of algae, such as brown algae (Phaeophyceae) and green algae (Chlorophyta). In Rhodophyceae, the main stored food is floridean starch, which is a complex carbohydrate similar to starch but with some structural differences. Algin and carrageenan are indeed products of algae, specifically brown algae (Phaeophyceae), and are used in various industrial applications, such as in food, pharmaceuticals, and cosmetics. Agar-agar, which is obtained from Gelidium and Gracilaria, is also a product of algae and is commonly used in laboratories for culturing microorganisms and in food as a gelling agent. Chlorella and Spirulina are types of green algae (Chlorophyta) that are used as dietary supplements and considered potential space food due to their high nutritional value.

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}