Import Question JSON

Current Question (ID: 12111)

Question:

In heterosporous members of the pteridophyta: 1. Development of embryo takes place within the female gametophyte 2. Zygote produces a multicellular and undifferentiated sporophyte 3. Gametophyte is monoecious 4. Spore germination is exosporic

Options:

1. Development of embryo takes place within the female gametophyte
2. Zygote produces a multicellular and undifferentiated sporophyte
3. Gametophyte is monoecious
4. Spore germination is exosporic

Solution:

Heterosporous members of the Pteridophyta, which includes plants like Selaginella and Salvinia, produce two types of spores: megaspores and microspores. Megaspores develop into female gametophytes, while microspores develop into male gametophytes. In heterosporous pteridophytes, the embryo develops within the female gametophyte after fertilization, which takes place when a sperm from a male gametophyte fertilizes an egg within the female gametophyte. This is in contrast to homosporous pteridophytes, where the embryo develops within the sporophyte. Option 2 is incorrect because in heterosporous pteridophytes, the zygote develops into a multicellular and differentiated sporophyte, not an undifferentiated one. Option 3 is incorrect because the gametophyte in heterosporous pteridophytes is dioecious, meaning male and female gametophytes are separate individuals, not monoecious where male and female gametophytes are present in the same individual. Option 4 is incorrect because spore germination in heterosporous pteridophytes is endosporic, meaning the spores germinate while still enclosed within the sporangium, and not exosporic where the spores germinate after being released from the sporangium.

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}