Import Question JSON

Current Question (ID: 12127)

Question:

Selaginella and Salvinia are considered to represent a significant step towards the evolution of seed habit because:

Options:

1. Embryo develops in female gametophyte which is retained on parent sporophyte.
2. Female gametophyte is free and gets dispersed like seeds.
3. Female gametophyte lacks archegonia.
4. Megaspores possess endosperm and embryo surrounded by a seed coat.

Solution:

Selaginella and Salvinia are heterosporous fern allies that produce two types of spores - microspores and megaspores. Microspores develop into male gametophytes and megaspores develop into female gametophytes. The female gametophyte of Selaginella and Salvinia is retained on the parent sporophyte and the embryo develops within the female gametophyte. This represents a significant step toward the evolution of the seed habit, as the embryo is protected and nourished within the parent sporophyte. The female gametophyte is not free and dispersed like seeds, as stated in option 2. Option 3 is incorrect, as the female gametophyte of Selaginella and Salvinia does possess archegonia, which are the female reproductive structures that produce eggs. Option 4 is incorrect, as the megaspore of Selaginella and Salvinia does not possess endosperm or a seed coat. The embryo is protected by the female gametophyte, but this is not equivalent to a seed coat.

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}