Import Question JSON

Current Question (ID: 12143)

Question:

Identify the incorrect statement:

Options:

1. Numerical Taxonomy is based on all observable characteristics.
2. More weightage is given to reproductive characters and all other characters are given equal importance in numerical taxonomy.
3. Cytotaxonomy is based on cytological information like chromosome number, structure, behaviour
4. Chemotaxonomy uses the chemical constituents of the plant

Solution:

All characters are given equal weightage in numerical taxonomy. Page 30, XI NCERT. Option 2 is incorrect. In numerical taxonomy, also known as phenetics, all characters are given equal weightage regardless of whether they are reproductive or non-reproductive characters. This statement implies that more weightage is given to reproductive characters, which is not accurate. Options 1, 3, and 4 are correct. Numerical Taxonomy is based on all observable characteristics, including both reproductive and non-reproductive characters. Cytotaxonomy is indeed based on cytological information such as chromosome number, structure, and behavior. Chemotaxonomy, on the other hand, uses the chemical constituents of plants as a basis for classification and identification.

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}