Import Question JSON

Current Question (ID: 12147)

Question:

Identify the incorrect statement: 1. The earliest systems of classification used only gross superficial morphological characters. 2. Linnaeus classification of plants was a natural classification as it was based on the androecium structure. 3. Artificial systems gave equal weightage to vegetative and sexual characteristics. 4. Natural classification systems are based on natural affinities among the organisms

Options:

1. The earliest systems of classification used only gross superficial morphological characters.
2. Linnaeus classification of plants was a natural classification as it was based on the androecium structure.
3. Artificial systems gave equal weightage to vegetative and sexual characteristics.
4. Natural classification systems are based on natural affinities among the organisms

Solution:

Option 2 is incorrect. Linnaeus' classification of plants, also known as the binomial system of nomenclature, was not based solely on the androecium (male reproductive structure) but rather on a combination of multiple morphological characters, including vegetative and reproductive characteristics. Options 1, 3, and 4 are correct. The earliest systems of classification did primarily use gross superficial morphological characters for classification. Artificial systems of classification, as the name implies, artificially grouped organisms based on selected characteristics, giving equal weightage to both vegetative and sexual characteristics. Natural classification systems, on the other hand, are based on the overall similarity and affinities among organisms, including their morphological, physiological, genetic, and ecological characteristics, and aim to reflect the natural relationships among organisms.

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}