Import Question JSON

Current Question (ID: 12157)

Question:

Read the statement (a - d): a. The male and female gametophytes do not have independent existence. b. The multicellular female gametophyte is also retained within megasporangium. c. The gametophytic generation is reduced. d. Sporophylls are aggregate to form cone like structures. The above statements belong to which group of plant kingdom?

Options:

1. Bryophytes
2. Pteridophytes
3. Gymnosperms
4. Angiosperms

Solution:

The statements (a - d) mentioned in the question are characteristic features of gymnosperms, which are a group of seed-producing plants with naked seeds and no flowers or fruits. Gymnosperms include plants such as conifers (e.g., pine, spruce, fir), cycads, ginkgoes, and gnetophytes. Option 1 (Bryophytes) is incorrect as the statements do not match the characteristics of bryophytes, which are non-vascular plants including mosses, liverworts, and hornworts. Option 2 (Pteridophytes) is incorrect as the statements do not match the characteristics of pteridophytes, which are vascular plants including ferns, horsetails, and clubmosses. Option 4 (Angiosperms) is incorrect as the statements do not match the characteristics of angiosperms, which are flowering plants including both monocots and dicots.

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}