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Current Question (ID: 12268)

Question:
Which of the following zone of the root has thin cell wall, dense cytoplasm and large nucleus?
Options:
  • 1. Region of maturation
  • 2. Region of elongation
  • 3. Region of root hair
  • 4. Region of meristematic cells
Solution:
The region of meristematic cells, also known as the meristematic zone or apical meristem, is the growing tip of the root where cell division and growth occur. In this region, the cells have thin cell walls, dense cytoplasm, and large nuclei. These characteristics enable rapid cell division and elongation, leading to root growth. The region of maturation is located above the meristematic zone and is where cells undergo specialization and differentiation into various cell types, such as root hairs, epidermal cells, cortex cells, and vascular tissue. The region of elongation is located above the region of maturation and is where the newly formed cells from the meristematic zone elongate and expand, pushing the root tip further into the soil. The region of root hairs is located just above the region of maturation and is where specialized root hair cells develop from the epidermal cells. Root hairs are responsible for absorbing water and nutrients from the soil. It's important to note that the specific characteristics of root zones may vary depending on the plant species and the developmental stage of the root. However, in general, the region of meristematic cells is characterized by thin cell walls, dense cytoplasm, and large nuclei due to active cell division and growth.

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}