Import Question JSON

« Back to Question List Edit Question »

Current Question (ID: 12318)

Question:
Match the Column-I and Column-II with Column-III: Column-I | Column-II | Column-III A. Marginal | I. | a. Sunflower, Marigold B. Axile | II. | b. Dianthus, Primrose C. Parietal | III. | c. Mustard, Argemone D. Free Central | IV. | d. Chinarose, Tomato, Lemon E. Basal | V. | e. Pea
Options:
  • 1. A - V, e; B - II, d; C - I, c; D - III, b; E - IV, a
  • 2. A - I, e; B - II, d; C - III, c; D - IV, b; E - V, a
  • 3. A - V, a; B - II, d; C - I, b; D - III, c; E - IV, e
  • 4. A - V, a; B - III, b; C - II, d; D - I, e; E - IV, c
Solution:
1. Marginal: In marginal placentation the placenta forms a ridge along the ventral suture of the ovary and the ovules are borne on this ridge forming two rows, as in pea. 2. Axile: When the placenta is axial and the ovules are attached to it in a multilocular ovary, the placentation is said to be axile, as in china rose, tomato and lemon. 3. Parietal: In parietal placentation, the ovules develop on the inner wall of the ovary or on peripheral part. Ovary is one-chambered but it becomes two-chambered due to the formation of the false septum, e.g., mustard and Argemone. 4. Free-central: When the ovules are borne on central axis and septa are absent, as in Dianthus and Primrose the placentation is called free central. 5. Basal: In basal placentation, the placenta develops at the base of ovary and a single ovule is attached to it, as in sunflower, marigold.

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}