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Current Question (ID: 12426)

Question:

All of the given characteristics are related to parenchyma tissue except

Options:

1. Composed of living cells
2. Generally isodiametric cells
3. Cell wall is mainly made up of suberin
4. Either closely packed cells with no intercellular spaces or have small intercellular spaces

Solution:

Parenchyma tissue is composed of living cells, generally isodiametric cells (meaning they have similar dimensions in all directions), and can either have closely packed cells with no intercellular spaces or have small intercellular spaces. However, the cell wall of parenchyma tissue is not mainly made up of suberin, which is a waxy material found in the cork cells of the cork tissue. The cell wall of parenchyma tissue is typically composed of cellulose, hemicellulose, and pectin.

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}