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Current Question (ID: 12437)

Question:

Choose odd with respect to collenchyma

Options:

1. Living mechanical tissue
2. Intercellular space is absent in angular type
3. Thickening of the wall is due to deposition of lignin
4. Found in hypodermis of dicot stem

Solution:

Collenchyma is a type of living mechanical tissue that provides support and flexibility to plant organs. It is characterized by elongated cells with irregularly thickened primary cell walls. The thickening of the cell walls in collenchyma is due to the deposition of cellulose, hemicellulose, and pectin, which provide mechanical strength to the tissue. Option 3 is incorrect because collenchyma cells do not contain lignin in their cell walls. Lignin is a complex polymer that is typically found in the secondary cell walls of certain types of cells, such as tracheids, vessels, and sclerenchyma cells. Collenchyma cells have primary cell walls that are thickened by cellulose, hemicellulose, and pectin, but not lignin. Options 1, 2, and 4 are correct because collenchyma is a living mechanical tissue, angular type of collenchyma cells do not have intercellular spaces, and collenchyma is commonly found in the hypodermis (outer cortex) of dicot stems.

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Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}