Import Question JSON

Current Question (ID: 12453)

Question:

Phloem in angiosperm is composed of a. Sieve tube element b. Companion cell c. Phloem parenchyma d. Phloem fibres e. Tracheids f. Vessels

Options:

1. a,b,c,d
2. b,c,d,e
3. c,d,e,f
4. None

Solution:

Phloem in angiosperms, which are flowering plants, is composed of sieve tube elements, companion cells, phloem parenchyma, and phloem fibers. Sieve tube elements are specialized cells that form the conducting elements of the phloem, responsible for the transport of organic nutrients such as sugars and other molecules. Companion cells are adjacent nucleated cells closely associated with sieve tube elements, providing energy and regulatory functions to support phloem transport. Phloem parenchyma refers to the type of ground tissue composed of living cells associated with the phloem, which may have various functions including storage and metabolism. Phloem fibers are elongated cells with thick cell walls that provide mechanical support to the phloem tissue. Tracheids and vessels, on the other hand, are types of cells that are part of the xylem tissue, responsible for water and mineral transport in plants, and are not part of the phloem tissue.

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}