Import Question JSON

Current Question (ID: 12455)

Question:

What is incorrect for companion cell?

Options:

1. It is specialized parenchymatous cell.
2. It helps in maintaining the pressure gradient in the sieve tubes.
3. It does not retain nucleus throughout the life.
4. It is absent in gymnosperms.

Solution:

Companion cells are specialized parenchymatous cells that are closely associated with sieve tube elements in the phloem tissue of flowering plants. They are connected to the sieve tube elements by numerous plasmodesmata and help in the loading and unloading of sugars into and out of the sieve tubes. Companion cells are highly metabolically active and have a large nucleus and dense cytoplasm, and they retain their nucleus throughout their life. Therefore, option (3) is incorrect. Options (1), (2), and (4) are correct statements about companion cells. Option (4) is true as companion cells are absent in gymnosperms, which have albuminous cells associated with the sieve tube elements.

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}