Import Question JSON

Current Question (ID: 12466)

Question:

Stomata in grass leaves are:

Options:

1. Dumb-bell shaped
2. Kidney shaped
3. Rectangular
4. Barrel-shaped

Solution:

Stomata are tiny apertures found on the epidermis of leaves and young green stems. Each stoma is surrounded by two specialized epidermal cells, called guard cells. these guard cells are bounded by one or more modified epidermal cells called subsidiary cells or accessory cells. The major role of stomata is to facilitate gas exchange and also facilitate transpiration, which helps the absorption of water from the soil and the transport of water through the xylem. The size of the stomata is controlled by a pair of guard cells. The main difference between the stomata of monocot and dicot plants is that the guard cells of the monocots are dumbbell-shaped. In Dicotyledonous leaf lower surface has a greater number of stomata while Monocotyledonous leaf they are about equal on both sides. In Dicot, the guard cells of Dicot plants are bean-shaped while in Monocots guards, cells are ellipsoidal or dumbbell-shaped, called graminaceous and poaceous stomata. PAGE 89, XI NCERT

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}