Import Question JSON

Current Question (ID: 12483)

Question:

In Ground tissue system, parenchymatous cells are usually present in

Options:

1. cortex
2. pericycle
3. pith and medullary rays
4. All of the above

Solution:

Parenchymatous cells, which are thin-walled and capable of cell division, are typically present in various regions of the ground tissue system in plants. This includes the cortex, pericycle, pith, and medullary rays. The cortex is the region of ground tissue between the epidermis and vascular tissue in stems and roots, and it often contains parenchymatous cells. The pericycle is the region of ground tissue located just inside the endodermis in roots, and it is involved in lateral root development and repair. The pith is the central region of ground tissue in stems, and it is typically composed of parenchymatous cells. The medullary rays are radial bands of parenchymatous cells that extend from the pith to the periphery of stems and roots, and they play a role in lateral transport of water and nutrients. Therefore, option 4, which states that parenchymatous cells are usually present in cortex, pericycle, pith, and medullary rays, is the correct answer.

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}