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Current Question (ID: 12498)

Question:
The cells which give rise to a part of vascular cambium in main root and lateral roots are
Options:
  • 1. Parenchymatous cells of pericycle.
  • 2. Collenchymatous cells of endodermis.
  • 3. Parenchymatous cells of endodermis.
  • 4. Meristematic cells of cortex.
Solution:
The cells which give rise to a part of vascular cambium in the main root and lateral roots are parenchymatous cells of pericycle. The pericycle is a single layer of parenchymatous cells that surrounds the vascular tissue in roots. It is a source of lateral roots and, in some cases, contributes to the formation of secondary growth. The pericycle can undergo cell division to form a lateral meristem or vascular cambium that produces secondary xylem and phloem. The collenchymatous cells of endodermis provide mechanical support to the root, and the parenchymatous cells of endodermis are involved in selective absorption of nutrients. Meristematic cells of the cortex are responsible for the primary growth of the root.

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}