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Current Question (ID: 12512)

Question:
Tissue which provides mechanical strength and flexibility to young dicot stem is present in
Options:
  • 1. Pith
  • 2. Endodermis
  • 3. Hypodermis
  • 4. Cortex
Solution:
The hypodermis is a layer of tissue that is present below the epidermis in young dicot stems. It is composed of collenchyma cells, which are elongated and have thickened cell walls. Collenchyma cells provide mechanical strength and flexibility to the stem, allowing it to withstand mechanical stresses and bending without breaking. Collenchyma cells have a primary cell wall that is thickened at the corners, providing structural support to the stem while still allowing for some flexibility. Pith is the central region of the stem, consisting of parenchyma cells and sometimes non-living elements like air spaces. It is not directly involved in providing mechanical strength or flexibility to the stem. Endodermis is a specialized layer of cells that surrounds the vascular tissue in the root, and it is not typically present in stems. Cortex is the region of tissue between the epidermis and the vascular tissue in stems, and it may contain various types of cells, including parenchyma, collenchyma, and sclerenchyma. While cortex may provide some mechanical support to the stem, it is not specifically responsible for providing mechanical strength and flexibility to young dicot stems as the hypodermis does.

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}