Import Question JSON

Current Question (ID: 12537)

Question:

Mark the correct one with respect to bundle sheath in a dicot leaf

Options:

1. Sclerenchymatous
2. Collenchymatous
3. Parenchymatous
4. Lignified

Solution:

The bundle sheath in a dicot leaf is usually parenchymatous. The bundle sheath is a layer of cells that surrounds the vascular bundles in leaves. In dicot leaves, the bundle sheath is typically composed of parenchyma cells, which are thin-walled and unspecialized cells that perform a variety of functions, including storage, photosynthesis, and support. The parenchyma cells in the bundle sheath are involved in the transport of sugars and other nutrients between the vascular bundles and the rest of the leaf. Sclerenchyma and collenchyma are types of mechanical tissue that provide support to the plant, but they are not typically found in the bundle sheath of dicot leaves. Lignified refers to the presence of lignin, which is a component of the cell wall that provides structural support to plant cells. While some cells in the bundle sheath may have lignified cell walls, this is not a defining characteristic of the bundle sheath in dicot leaves.

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}